Wednesday, February 17, 2010

Index.of Jpg In Tights Light Refracted Through A Prism 2?

Light Refracted through a Prism 2? - index.of jpg in tights

Search the largest value that the angle of May without light refracted through the prism of the face of the CA if the prism is immersed in water (1.33) with a refractive index.
Express your answer in degrees. Ignoring surface reflections of British Columbia.

http://i54.photobucket.com/albums/g99/ca ...

1 comments:

Fizz_Ass... said...

The angle of incidence of light on the surface of AC (90-alpha). This must be greater than the critical angle for TIR occur.

Sin (critical angle) = refractive index of water / index glass refractice = 1.33/1.58 = 0.0.842

Critical angle = sin-1 0.633 = 57.33 degrees

Alpha = 90 (or more) 57.33
\\ \\ \\ \\ Alpha \\ \\ \\ \\ u0026lt; (or equivalent) of 90 to 39.27 = 32.67 degrees

Maximum angle of alpha is 32.67 degrees

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